a/(b+c) = 5/7 c/(a+b) = 2/3
So, 5b+5c = 7a and 3c = 2a+2b
5c = 7a-5b so, c = (7/5)a - b
Since 3c = 2a+2b, c = (2/3)a + (2/3)b
Therefore, (7/5)a - b = (2/3)a + (2/3)b
(11/15)a = (5/3)b So, b = (3/5)(11/15)a = (11/25)a
c = (2/3)a + (2/3)b = (2/3)a + (11/25)a = (83/75)a
So, (a+2b) / (b+2c) = [a + (22/25)a] / [(11/25)a + (166/75)a]
= [(47/25)a] / [(199/75)a] = (47/25)(75/199) = 141/199