helpmeplease

Question

Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a queen for the second card drawn, if the first card, drawn without replacement, was a queen? Express your answer as a fraction or a decimal number rounded to four decimal places

 

Answer 1

The probability of drawing a queen for the second card is 3/51=1/17 because there are 3 remaining queens and 51 cards left to choose from after your first card drawn is a queen.

Answer 2

P(A) = n(A)/n(S)

• P(A) = probability of event A
• n(A) = number of ways event A can occur
• n(S) total number of possible outcomes

 

A standard deck has 52 cards.  After 1 draw without replacement, there are 51 cards left, so n(S) = 51.

There are four queens in a deck.  If the first card is a queen, then there are 3 queens left, so n(A) = 3.

 

P(Q on second draw) = 3/51 = 1/17

Answer 3

3 / 51

 

You can convert to decimal.