algebra.Please help me

Question

The area of a rectangle is 63 m2 , and the length of the rectangle is 5 m more than twice the width. Find the dimensions of the rectangle.

Answer 1

algebra.Please help me
The area of a rectangle is 63 m2 , and the length of the rectangle is 5 m more than twice the width. Find the dimensions of the rectangle.

 

Solution:

 

let L be the length of the rectangle and W be the width

 

the length of the rectangle is L =2W+5m from the problem statement

You also know that the area of the rectangle is LW=63m² given

 

from the second equation L = 63/W substitute in the eq L =2W+5

 

then 63/W=2W+5 ---Multiply by W , 63 = 2W²+5W rearranging terms

 

2W²+5W-63=0 Solve quadratic equation

 

W=-5±√5²-4(2)(-63)/4 = -5±√529/4=-5±23/4 two solutions for W

 

W=-5-23/4= -28/4=-7,  W=-5+23/4=18/4=4.5 No W cannot be negative then  W = 4.5 m , and L =63/4.5=14 m

 

Check L =2W+5, 14=2(4.5)+5=9+5=14 checks