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2 dimensional motion problem

A small steel ball is projected horizontally off the top of a long flight of stairs. The initial speed of the ball is 3.4 m/s. Each step is 0.19 m high and 0.29 m wide. Which step does the ball strike first?

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1 Answer

I am going to work this problem in two parts.  First, I am going to only deal with vertical components to find out how much time it takes the ball to reach the first step:


a = g = -9.81 m/s2

vi= 0 m/s

xi = 0 m

xf = -.19 m

1/2at2 + vit + xi = xf

1/2(-9.81)t2 + 0t + 0 = -.19

t2 = 2*(-.19)/(-9.81)

t = .0387 s

Now, we will determine how far the ball traveled horizontally in this time.


v = 3.4 m/s

t = .0387 s

v = x/t

x = vt

x = 3.4*(.0387)

x = .132 m

Therefor, the ball strikes the top step.  It would have to travel .29 m horizontally before dropping .19 m vertically in order to not hit the top step.