A spring has a concert at 450 N per meter how much must the spring be stretched to store 49 J of potential energy

Question

I need to know this for my hw

Answer 1

Student,

 

I am pretty sure you meant to say that the spring has a CONSTANT of 450 N per meter, not a CONCERT of 450 N per meter.

 

U(x) = kx²/2 ⇒

 

x = √(2U/k) = √[2(49)/450] m = ? m