**M = f**

_{o}/f_{e}- M = magnification = 60
- f
_{o}= focal length of the telescope = 6.33 m = 633 cm - f
_{e}= focal length of eyepiece

M = f

_{o}/f_{e}60 = 633/f

_{e}Solve for f

_{e}. The units will be cm.Jason N.

asked • 03/20/18Please be aware that you need to use centimeters instead of meters for the answer in this question. This is different than the practice test.

If you build a telescope with a focal length of 6.33 m, what should the focal length in centimeters of your eyepiece be if you want a magnification of 60. Give your answer to two decimal places and include the unit cm for centimeter in your answer.

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- M = magnification = 60
- f
_{o}= focal length of the telescope = 6.33 m = 633 cm - f
_{e}= focal length of eyepiece

M = f_{o}/f_{e}

60 = 633/f_{e}

Solve for f_{e}. The units will be cm.

Arturo O. answered • 03/20/18

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magnification = (focal length of objective)/(focal length of ocular)

M = magnification = 60

focal length of objective = 6.33 m

focal length of ocular = focal length of eyepiece = x

60 = (6.33 m)/x ⇒

x = (6.33 m)/60 = 0.1055 m = 10.55 cm

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