R = -2x2 + 2000x
There are two ways to find the maximum revenue, using calculus and using algebra.
CALCULUS
Take the derivative of R wrt x, set it to zero, and solve for x. Setting the derivative to zero will find the extreme points (maximums and/or minimums) of the function.
dR/dx = -4x + 2000
0 = -4x + 2000
4x = 2000
x = 500
Plug x = 500 into the revenue equation to get the max revenue.
ALGEBRA
The revenue equation is a quadratic, so its graph is a parabola. Since the coefficient of the x2 term is negative (-2), it's an inverted parabola with the vertex at the top. The vertex will thus be the maximum revenue. To find the vertex, convert R to the vertex form R = a(x-h)2+k where (h,k) is the location of the vertex. Convert to the vertex form by completing the square:
R = -2x2 + 2000x
R = -2(x2 - 1000x + 250,000) + 500,000
R = -2(x-500)2 + 500,000
The vertex is located at x=500 and R = $500,000. The max Revenue is thus $500,000.