g(x) = -1/x
g(3) = -1/3
f(g(3)) = f(-1/3) = [-1/3] = -1
If you plot -1/3 on a number line (below). the solution for ≤ -1/3 lies from -1/3 to the left. The first integer you bump into is -1. As you go further left, the numbers get more negative and hence smaller. So the largest integer ≤ -1/3 is -1.
-1/3
<-----|------|------|-----]--|--------|--------|-------->
-3 -2 -1 0 1 2