find the 60th term of the sequence 0.6,1...

Question

The question is from Arithematic Sequency

Answer 1

If this is an arithmetic sequence then the common difference is

d =0.4   because 1-0.6 =0.4 showing that we add 0.4 to any given

term to find the next term in the sequence.

 

So to find a term from the previous term we use a_n = a_n-1 + 0.4

For this problem we need:  a_n = a₁ + (n-1)d

To get from a₁ to a₆₀ we add 0.4 a total of 59 times

 

a₆₀ = a₁ + 59d

a₆₀ = 0.6 + 59(0.4)

a₆₀ = 24.2

Answer 2

If 0.6 and 1 are the first two terms of an arithmetic sequence, then the common difference, d, is given by

d = 1 - 0.6 = 0.4. 

 

The 60th term, a₆₀, is:  a₆₀ = a₁ + (60-1)d = 0.6 + 59(0.4) = 24.2