Arturo O. answered • 03/07/18

Experienced Physics Teacher for Physics Tutoring

_{c}= rω

^{2}= (0.0750 m) [2π(7500)/(60 s)]

^{2}= ? m/s

^{2}

_{c}/g = a

_{c}/(9.8 m/s

^{2})

_{c}and divide by 9.8 m/s

^{2}.

Brook T.

asked • 03/07/18An ordinary workshop grindstone has a radius of 7.50 cm and rotates at 7500 rev/min. A.) Calculate the magnitude of the centripetal acceleration at its edge in meters per second squared and convert it to multiples of g. B.) An ordinary workshop grindstone has a radius of 7.50 cm and rotates at 7500 rev/min. What is the linear speed in m/s of a point on its edge (in m/s)?

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Arturo O. answered • 03/07/18

Tutor

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(66)
Experienced Physics Teacher for Physics Tutoring

(A)

a_{c} = rω^{2} = (0.0750 m) [2π(7500)/(60 s)]^{2} = ? m/s^{2}

In terms of g's,

a_{c}/g = a_{c}/(9.8 m/s^{2})

Just plug in the result for a_{c} and divide by 9.8 m/s^{2}.

(B)

v = rω

r = 0.0750 m

ω = 2π(7500)/(60 s)

v = (0.0750 m) [2π(7500)/(60 s)] = ? m/s

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Arturo O.

03/07/18