Give the quotient and remainder of 1783 divided by 3

Question

I need to know the quotient and remainder of 1783 Divided by 3

Answer 1

Let's set up the long division problem:

 

  --------

3|1783

 

Three cannot go into 1, so we carry over to the next number, 7. The 1 in the tens and 7 in the ones gives us 17. By multiplying 3 times 5 we get 15, because we don't want to go over the 17:

    5

  --------

3|1783

  -15

  --------

     2

We now drop the 8 down next to the 2, giving us 28. 3 times 9 gives 27, so the problem now looks like:

    59
  --------
3|1783
  -15
  --------
     28

     -27

    --------

        1

We drop the 3 down, which dives us 13. When we multiply 3 times 4, we get 12:

    594
  --------
3|1783
  -15
  --------
     28
     -27
    --------
        13

       -12

        -------

           1

We have nothing left to drop, so we have a remainder of 1, and thus our final answer is 594 R1

 

Answer 2

         594

   _________

3 |    1783

        15

      ---------

          28

          27

      ----------

            13

            12

     ----------

              1

 

 

THe answer is 594 with remainder 1.

 

CHECK:

 

  594 x 3 =   (500 + 90 + 4) x 3 

              =   1500 + 270 + 12  <--- partial products

               =   1770 + 12

              =  1782

 

   Then you add the remainder of 1, which makes 1783, so it checks!