Philip P. answered • 03/04/18

Effective and Patient Math Tutor

sec(θ+45°) = 1/cos(θ+45°)

1/cos(θ+45°) = 1

1 = cos(θ+45°)

The cosine equals one at 0

^{o}± k·360°, k = 0, 1, 2, 3, ... Solve for θ.Michael F.

asked • 03/04/18We are doing simple trig equations, you know, where like 1/2 =cos(theta) and you find on the trig circle what that is equal to. So it would be 60 and 300 degrees. However, I don't know how to solve this problem:

sec( theta+45)=1

Please help! Thanks!

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Philip P. answered • 03/04/18

Effective and Patient Math Tutor

sec(θ+45°) = 1/cos(θ+45°)

1/cos(θ+45°) = 1

1 = cos(θ+45°)

The cosine equals one at 0^{o} ± k·360°, k = 0, 1, 2, 3, ... Solve for θ.

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Michael F.

03/04/18