r=6sin(3θ)
r2+(dr/dθ)2=36sin2(3θ)+9*36cos2(3θ)=36(1-cos2(3θ)+9cos2(3θ))
=36(1+8cos2(3θ)
∫0π/36√[1+8cos2(3θ)]dθ=10π
∫0π6√[1+8cos2(3θ)]dθ=30π
Probably somewhere a mistake with integration.
Hannah O.
asked 03/03/18
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