
Victoria V. answered 02/27/18
Tutor
5.0
(402)
20+ years teaching Algebra 2 subjects & beyond.
The surface area of a right cylinder is the area of the top circle (pi*r^2), the area of the bottom circle (pi*r^2), and the area of the curved-around side (2*pi*r*h).
The volume of a right cylinder is pi*r^2*h.
Since h = 2r,
Surface area becomes pi*r^2 + pi*r^2 + 2*pi*r*(2r) <--- this (2r) = h
or Surface area = 2(pi*r^2) + (4*pi*r^2)= 6 pi r^2
Volume (using h=2r) = pi*r^2(2r) = 2 pi r^3
The ratio of these is:
6 pi r^2
----------
2 pi r^3
6
-- = 3
2
pi
--- = 1
pi
r^2 1
----- = --------
r^3 r
Putting all of this together,
Surface Area 3
--------------- = --------------------
Volume r