en has four more than twice as many CDs as Jake. If they have a total of 31 CDs, what percentage, to the nearest whole, of the total does Jake have?

Question

Trying to find the percentage...

Answer 1

Let A = Allen's number of CDs   (en = Allen?)

 

      J = Jake's number of CDs

 

1) A = 2*J + 4   or rearrange as  A  - 2*J  = 4

 

2)                                           -[A  +  J   = 31]

                                             -------------------

Subtract  eqn 2) from eqn 1):

 

                                               0 - 3*J  = - 27

 

or  J  =  -27/-3  = 9 CDs that Jake has

 

     Therefore, the % of CDs that Jake has = 9/31 x 100%  = 29%