
Stephen K. answered 09/04/14
Tutor
4.9
(798)
Physics PhD experienced in teaching undergraduates
Usama,
Forget for a moment that the quotient is 2 and consider a more general solution such that:
Let x = larger number and y = smaller number, and Q = quotient.
Then x÷y = Q (+2 remainder)
and 5y÷x = Q (+2 remainder)
we can rewrite these as x = Qy (+2 remainder) so x = Qy + 2
and 5y = Qx (+2 remainder) so 5y = Qx +2
No replace Q with the value of the quotient Q = 2 and our two equations become:
x = 2y + 2
5y = 2x + 2
substituting for x in the 2nd equation gives:
5y = 2(2y + 2) + 2 = 4y + 4 +2 = 4y + 6
5y - 4y = y = 6
So y = 6 then x = 14
Check: x/y = 14/6 = 2 + (remainder 2)
(5·y)/x = 30/14 = 2 + (remainder 2)