
Bobosharif S. answered 02/17/18
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(4a2+3a+2)/(a3-1)-(1-2a)/(a2+a+1)=
= (4a2+3a+2)/((a-1)(a2+a+1))-(1-2a)/(a2+a+1)=
=(1/(a2+a+1)) ((4a2+3a+2)/(a-1)-1+2a))=
=(1/(a2+a+1)) ((4a2+3a+2-a+1+2a2-2a)/(a-1))
=(1/(a2+a+1)) ((6a2+3)/(a-1))
=3(2a2+1)/(a3-1).

Bobosharif S.
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02/17/18
MARVIN Z.
02/17/18