
Arturo O. answered 02/14/18
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Use the kinematic relation
v2 - v02 = 2ad
with
v0 = 0
d = 200 meters
a = f/m = (μmg)/m = μg
μ = 1
v2 = 2ad
v = √(2ad) = √[2(μg)(d)] = √[2(1)(9.8)(200)] m/s ≅ 62.61 m/s