Kim Z. answered • 02/07/18
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Math Tutor and Coach
is this what you are looking at: 1/[5x3*(x-1)] + 1/[ 6(x+2)(x-1)4] or something similar?
if so, you have (x-1) in common so just multiply the first one by 6(x+2)(x-1)3/6(x+2)(x-1)3 and multiply the second one by 5x3/5x3 to create a common denominator.
Edward A.
as Kim Z. points out, we think the problem is typed wrong.
The way I read your problem, it is
5(x+3)2(x-1), 6(x+2)(x-1)4
but that gives no GCD.
perhaps you meant a different exponent
5(x+3)2(x-1), 6(x+2)(x-1)4
that would allow (x-1) to be the GCD.
Why would you suggest (x+2)? Maybe because of another typo? Maybe it is supposed to be
5(x+2)2(x-1), 6(x+2)(x-1)4
if so, then yes (x+2)(x-1) would be the GCD.
My sympathy, I find it hard to type formulas on my phone, but if it isn’t exactly right, our guidance is based on our ability to guess what the original problem is.
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02/07/18
Stephanie K.
5(x+3)2 * (x-1), 6(x+2)(x-1)4
This is what I intended it to be! It is hard to type these equations out, lol.
For this particular problem, how would I find the LCM?
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02/07/18
Kim Z.
so the least common multiple would be: 30(x+3)2*(x-1)4*(x+2)
Notice: The only item not included would be the other (x-1) because it is already captured in (x-1)4
When we can't find any or many common multiples between them, we just multiply them together. Here the only common item is the (x-1)
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02/11/18
Stephanie K.
02/07/18