A confusing question for me. Help please
I have answered the first question, but the second one is little confusing for me.
Archery An arrow is shot at 30.0o above the horizontal. Its velocity is 49m/s, and it hits the target.
a. What is the maximum height the arrow will attain?
Answer: (49sin30)2/2*9.8 = 30.625m
b. The target is at the height from which the arrow was shot. How far was it?