
Andrew M. answered 02/06/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
distance = rate*time
d = 30(2.5) = 75 km
Decreasing rate to 20 km/hr gives:
75 = 20t
t = 75/20
t = 3 3/4 hours