Bobosharif S. answered 02/05/18
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Mathematics/Statistics Tutor
Volume of the solid, generated by the revolving around x-axis is found by
S=π∫[f(x)]2dx, Integration bounds 0 and 2
S=π∫(2x+4)2dx=4π∫(x+2)2dx =4π(x+2)3/3|0 2=(4π/3)(53-23)=..
=(4π/3)(7)(19).
Since y=2x+4 is linear function, therefore when revolving around x-axis the solid body would be a cone. Height of the cone h equals to 2 and the radius of the basic is 8 (2*2+4). So you can find a volume of the cone with those parameters as well: h=2, r=8.