Can anyone answer this question

Question

At a factory that produces pistons for cars, Machine 1 produced
606
satisfactory pistons and
404
unsatisfactory pistons today. Machine 2 produced
880
satisfactory pistons and
220
unsatisfactory pistons today. Suppose that one piston from Machine 1 and one piston from Machine 2 are chosen at random from today's batch. What is the probability that the piston chosen from Machine 1 is unsatisfactory and the piston chosen from Machine 2 is satisfactory ?

Answer 1

Probability of the two events = product of the individual probabilities.

P(piston from M1 is unsatisfactory) = 404/(404+606) = .4

p(piston from M2 is satisfactory) = 880/(880+220) = .8

 

probability of the two events = .4 * .8 = .32