Don L. answered 01/29/18
Tutor
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(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi Cindy, let w represent the width of the rectangle and l represent the length of the rectangle.
Given, the width, w, is equal to l - 2.
The area of the original rectangle would be, area = l * w, or area = l * (l -2), which gives the original area as l2 - 2l.
The width is reduced by 1 foot and the length is increased by 4 feet. The new area is given by, area = (l + 4) * (l - 1), or
l2 + 3l - 4.
The new area is equal to the original area plus 21 square feet.
Equation to solve:
New area = original area + 21
l2 + 3l - 4 = l2 - 2l + 21
The l2 terms cancel leaving:
3l - 4 = 2l + 21
Combine terms:
5l = 25
l = 5
The original length was 5 feet.
The original width was 5 - 2, or 3 feet.
The new length is 5 + 4, or 9 feet.
The new width is 5 - 1, or 4 feet.
The original area is 3 * 5, or 15 square feet.
The new area is 4 * 9, or 36 square feet.
The difference in areas, 36 - 15 = 21 square feet.
Questions?