
Arturo O. answered 01/28/18
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
Apply Newton's 2nd law (F = ma) to both masses, in the horizontal direction. Get 2 equations in the variables tension (T) and acceleration (a). Use one equation to eliminate acceleration, and then solve for tension in the other equation.
Right hand mass:
(i) (mg/2)cosθ - T = ma [T points left if (mg/2)cosθ points right]
Left hand mass:
(ii) T = (2m)a ⇒ a = T/(2m) [same a as in (i) since they accelerate together; T points right by Newton's 3rd law]
Plug a = T/(2m) into equation (i) and get
(mg/2)cosθ - T = m[T/(2m)] ⇒
(mg/2)cosθ - T = T/2
(mg/2)cosθ = (3/2)T
T = mg cosθ / 3
Answer (6) is correct.