Rock B.

asked • 01/27/18

Confusing simultaneous linear equation

a) 2 boys and 5 girls can finish a piece of work in 4 days . 4 boys and 4 girls can finish the same work in 3 days. If a girl is paid
$750 every day, what would be the total expenditure to complete the work?
Ans: $2700
 
b) 8 men and 12 women can finish a piece of work in 10 days, 6 men and 8 women can finish the same work in 14 days. how many days does each (1 man and 1 woman separately) need to complete the work?
Ans: 140days , 240 days

Mahdi G.

Let me revise the problem for you:
a) 2 boys and 5 girls can finish a piece of work in 4 days . 4 boys and 4 girls can finish the same work in 3 days. If a girl is paid $75 every day, what would be the total expenditure to complete the work just by herself?
Ans: $2700

b) 8 men and 12 women can finish a piece of work in 10 days, 6 men and 8 women can finish the same work in 14 days. how many days does each (1 man and 1 woman separately) need to complete the work?
Ans: 140 days , 280 days
Report

01/27/18

Rock B.

Thank you very much for this sir!!
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01/27/18

2 Answers By Expert Tutors

By:

Mahdi G. answered • 01/27/18

Tutor
4.5 (2)

I am not teaching, I am helping you to enjoy!

Andy C. answered • 01/27/18

Tutor
4.9 (27)

Math/Physics Tutor

Rock B.

The numbers are correct for both the  questions.
Their must be a way to solve it with the limited information that we have.
The answers seem to satisfy the question as well
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01/27/18

Mahdi G.

There are typos is the problem, I fixed it for you. The number $750 per day is not correct $75.0 gives the correct answer. Also, solving the second part gives 280 days for women and 140 for men. 
More importantly the is a missing sentence in part a, (check the comment I posted under your question)
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01/27/18

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