
Bobosharif S. answered 01/25/18
Tutor
4.4
(32)
PhD in Math, MS's in Calulus
(sin4x/(1-cos4x))*((1-cos2x)/cos2x)=
=2sin(2x) cos(2x)/(2sin2(2x))*2sin2(x)/cos(2x)
=cos(2x)/sin(2x)*2sin2(x)/cos(2x)=
=2sin2(x)/(2sin(x)cos(x))=sin(x)/cos(x)=tan(x)