
Arturo O. answered 01/25/18
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A(t) = amount present as a function of time
A(0) = initial amount = 1g
t = days
A(t) = A(0) (1/2)t/8
Solve for t in
0.0625 (1g) = (1g) (1/2)t/8
log0.0625 = (t/8) log0.5
t = 8 (log0.0625 / log0.5) days = 32 days

Arturo O.
01/25/18