algebra word problem

Question

In a certain season, a baseball player had a total of 106 hits. He hit three fewer triples than home runs, and he also hit three times as many doubles as home runs. Additionally, he hit 42 times as many singles as triples. Find the number of singles, doubles, triples, and home runs hit by the player during the season.

Answer 1

let h =  # of home runs

then # triples must be h-3

and # doubles must be 3h

and finally # singles = 42(h-3).

 

Total # of hits = 106 = h + h-3 + 3h + 42(h-3).

 

Solve the equation. Check results.  h must be an integer > 3.