Lori C. answered 01/19/18
Tutor
5.0
(21)
Algebra, Trigonometry and Calculus
Theoretically it can be zero, but not in this particular case.
Notice that if you add the number of girls in each activity, there are 39. Since there are 35 girls in the class, (39-35 = 4) says that at least 4 girls are in both.
It is possible that Mary is in the class but not in either activity. That would mean that 5 girls are in both.
Break the diagram into groups; A group of girls in dance, a group of girls in band, a group of girls in both and a group of girls in neither. Use a few individual names if that helps you see the possibilities.
Lori C.
This problem only gave you options of girls in one or both of the groups.
If there were 3 girls who did not participate in either, there would be 4 subgroups: Neither + Dance only + Band only + Both. That must add to 35.
Since we know that Neither = 3, we can say that Dance only + Band only + Both = 32.
Adding 18 + 21 = 39. so 39 - 32 = 7. That means 7 is Both.
We still have to contend with the 18 and 21 requirements. 18-7 = 11 and 21-7 = 14.
This is what we have:
Neither = 3
Dance only = 11
Band only = 14
Both = 7
Total = 35.
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01/19/18
Amy S.
01/19/18