
Victoria V. answered 01/14/18
Tutor
5.0
(402)
Math Teacher: 20 Yrs Teaching/Tutoring CALC 1, PRECALC, ALG 2, TRIG
Hi Vivian.
Let's do this one year at a time:
After 1 year: Start with $350 add the interest ($350)(.08) = $350 + $28 = $378 (not the $500 she wants)
After 2 years: Start with $378 and add the interest ($378)(0.08) = 378 + $30.24 = $408.24 (not the $500 she wants)
After 3 years: Start with $408.24 and add the interest ($408.24)(0.08) = $408.24 + $32.66 = $440.90 (not the $500 she wants)
After 4 years: Start with $440.90 and add the interest ($440.90)(0.08) = $440.90 + 35.27 = $476.17 (not the $500 she wants)
After 5 years: Start with $476.17 and add the interest ($476.17)(0.08) = $476.17 + $38.09 = $514.26 FINALLY! she has reached more than $500.
I don't know what grade-level you are in, so in whole years, the answer is 5 years.
If you have worked with logarithms, you can discover that it is actually 4.63 years, or 4 years and 7 months and 17 days.

Victoria V.
My pleasure! :-)
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01/15/18
VIvian A.
01/14/18