Arthur D. answered 01/10/18
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f(1)=10
f(n)=nf(n-1)+5
f(2)=2f(1)+5=2*10+5=25
f(3)=3f(2)+5=3*25+5=75+5=80
f(4)=4f(3)+5=4*80+5=320+5=325
f(5)=5f(4)+5=5*325+5=1625+5=1630

Arthur D.
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You're very welcome Emily.
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01/12/18
Emily V.
01/11/18