Eugene E. answered 12/30/17
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Suppose P is an n x n permutation matrix, and let s be the permutation associated with P. Let e1,..., en and e1,...,en be the n columns and n rows of the identity matrix I, respectively. Then ej P = es(j) for all j. Note
(PT ej)T = (ej)T (PT)T = eT P = es(j) = (es(j))T (j = 1,2,3,.., n)
and hence PT ej = es(j) for all j, showing that PT is a permutation matrix (with associated permuation s-1).
Since P is a real matrix, its adjoint PH equals PT, so PH is a permuration matrix.