The sum of two positive integers is 98.They are in ratio 3:4.Find the integers

Question

The sum of two consecutive integers

Answer 1

3x + 4x = 98

7x = 98

X=14

3x = 42

4x = 56

42+56=98

Answer 2

You appear to have 2 different problem statements, one in the title and one in the description.  I will assume the one in the title is correct, and I will work that one.

 

n + m = 98

 

n/m = 3/4

 

n = (3/4)m

 

(3/4)m + m = 98

 

(7/4)m = 98

 

m = (4/7)98 = 56

 

n = 98 - m = 98 - 56 = 42

 

Note that

 

n/m = 42/56 = 3/4