I need to solve using the substitution method, but I'm having trouble figuring out how to do it with this problem.

2y=x

^{2 }and y=4x^{3}I need to solve using the substitution method, but I'm having trouble figuring out how to do it with this problem.

2y=x^{2 }and y=4x^{3}

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Irvine, CA

Alex:

First equation gives y = x^{2} / 2. So x^{2} / 2 = 4 x^{3}, giving x = 1 / 8 and y = x^{2} / 2 = 1/128.

Check y = 4x^{3} = 4(1/512)= 1/ 128, 2y = 1/64 and x^{2 }= (1/8)^{2} = 1/64.

Dattaprabhakar (Dr.G.)

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## Comments

^{2}/2 = 4x^{3}but I don't understand how that becomes 1/8^{2}/ 2 = 4 x^{3}.isa solution but not interesting. So look for non-zero solutions. Then you can divide by x on both sides.)