
Andrew M. answered 12/13/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Hi Stac;
Cost as a function of # minutes, texts, pictures:
c(m,t,p) = 0.1m + 0.2t + 0.25p
Total cost for the month is $30.95:
0.1m + 0.2t + 0.25p = 30.95
multiply through by 100
10m + 20t + 25p = 3095 {equation 1}
total number of text and picture messages sent was 87:
t + p = 87 {equation 2}
minutes was $1.60 less than the cost of the text messages
0.1m = 0.2t - 1.6
multiply through by 10
m = 2t - 16 {equation 3}
Using equation 2, solve for t in terms of p
t = 87 - p
From equation 3:
m = 2(87-p) - 16
m = 174 - 2p - 16
m = 158 - 2p
We now have both t and m in terms of p
Plugging that information into equation 1:
10m + 20t + 25p = 3095
10(158-2p) + 20(87-p) + 25p = 3095
1580 - 20p + 1740 - 20p + 25p = 3095
3320 -15p = 3095
-15p = -225
p = 15 picture texts
m = 158-2p = 158 - 30 = 128 minutes used or 2 hours 8 minutes
t = 87 - p = 87 - 15 = 72 texts sent
I'll leave it to you to plug the answer into the original equations
and verify they balance.