A beaker contains 6mL of a chemical tht is 35% glycine, an important amino acid. How much of a another chemical that is 50% glycine should be added, so that the

Question

resultant chemical is 46% glycine? 

Answer 1

(6 ml)(35%) + (x ml)(50%) = (6 + x ml)(46%)

210 + 50x = 276 + 46x

4x = 66

x = 16.5 mls of the other solution should be added to give 22.5 mls of 46% glycine

 

Done by alligation:

Have......Want.....Need

35%....................4 parts...

..............46%.................

50%....................11 parts....

Total of 15 parts, and 4 parts = 6 ml so 11 parts must = 16.5 ml