Morris H.

asked • 08/08/14

Mike needs 10 lbs of metal with 36% silver. If mike combines one metal with 28% silver, and another with 61% silver, how much of each metal does Mike need?

I have the answer, just need to know how to work it.

2 Answers By Expert Tutors

By:

Morris H.

I tried doing what you said, I think,  and got answers that didn't work out. Would you mind explaining just a little more please?
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08/08/14

Stephen K.

tutor
Sure, Let y = 10-x
 
Then x*28 + (10-x)*61 = 360
 
28·x + 610 - 61·x = 360
 
Rearranging and collecting like terms:
 
33·x = 250
 
x = 250/33 =7.58 lbs
 
y = 10 - 7.58 = 2.42 lbs
 
Check:
 
7.58*28 + 2.42*61 = 212.2 + 147.6 = 359.8
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08/08/14

Stephen K.

tutor
I added additional work so that you can see how the numbers work out.  Hope this helps.
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08/08/14

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