Morris H.

asked • 08/08/14

# Mike needs 10 lbs of metal with 36% silver. If mike combines one metal with 28% silver, and another with 61% silver, how much of each metal does Mike need?

I have the answer, just need to know how to work it.

## 2 Answers By Expert Tutors

By:

Francisco E. answered • 08/08/14

Tutor
5 (1)

Francisco; Civil Engineering, Math., Science, Spanish, Computers.

Morris H.

I tried doing what you said, I think,  and got answers that didn't work out. Would you mind explaining just a little more please?
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08/08/14

Stephen K.

tutor
Sure, Let y = 10-x

Then x*28 + (10-x)*61 = 360

28·x + 610 - 61·x = 360

Rearranging and collecting like terms:

33·x = 250

x = 250/33 =7.58 lbs

y = 10 - 7.58 = 2.42 lbs

Check:

7.58*28 + 2.42*61 = 212.2 + 147.6 = 359.8
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08/08/14

Stephen K.

tutor
I added additional work so that you can see how the numbers work out.  Hope this helps.
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08/08/14

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