
Arturo O. answered 12/10/17
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Assume the ground telescope sees an object of brightness 1 at a distance d, and assume the Hubble sees the same object at a brightness of 1/50 at a distance ad. You know that brightness is inversely proportional to the square of the distance, so the product of brightness and distance squared is the same for both telecopes.
(1)d2 = (1/50)(ad)2
Solve for a.
a2 = 50
a = √50 ≅ 7.071 ≅ 7
Hubble can see the same object 7 times farther away than what the ground telescope can see.