Franklin P. answered 12/10/17
Tutor
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Professional Mechanical Engineer For Math & Science Tutoring
This question has 2 parts:
- Organizing the fractions from largest to smallest
- Subtracting the smallest fraction from the largest
First let's order the fractions. To do that, change all of the fractions so they have the same divisor (bottom of the fraction). The simplest way to make sure all the fractions have the same divisor is to just multiply by every divisor. For example:
Our divisors are 8, 6, 9, 2. So 8 * 6 * 9 * 2 = 864
Now multiply every number by the divisors it does not have:
For example - 5's divisor needs to be multiplied by 6, 9, 2
5 * 6 * 9 * 2 = 540
Do this for every number:
5/8 -> 540/864
2/6 -> 288/864
4/9 -> 382/864
1/2 -> 432/864
So our smallest fraction is 2/6 and our largest fraction is 5/8.
Now to subtract these let's do the same method to get a common divisor:
Divisor - 6 * 8 = 48
2 * 8 = 16
5 * 6 = 30
So our fractions become 16 / 48 and 30 / 48
Subtract them yields 14 / 48
14/48 can be reduced to 7/24.