Pierce O. answered 08/07/14
Tutor
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Graduate Mathematics Student, Will Tutor Any Math Subject
Hi Logan,
a. tan(θ)*cot(θ) - cos2θ = ( sin(θ)/cos(θ) ) * ( cos(θ)/sin(θ) ) - cos2θ (definition of tanθ and cotθ)
= 1 - cos2θ (tanθ*cotθ = 1)
= sin2θ (Pythagorean Identity)
b. ( 1 - sin(θ) )/( 1 + sin(θ) )
= ( 1 - sin(θ) )/( 1 + sin(θ) )*( ( 1 - sin(θ))/(1 - sin(θ)) ) (multiply by conjugate)
= ( 1 - 2sinθ + sin2(θ) )/( 1 - sin2(θ) ) (multiply through)
= ( 1 / (1 - sin2θ) - 2sinθ/(1 - sin2(θ)) + sin2(θ)/( 1 - sin2(θ) ) ) (seperate fractions)
= ( 1/cos2(θ) - 2sinθ/cos2(θ) + sin2(θ)/cos2(θ) ) (Pythagorean Identity)
= sec2(θ) - 2sec(θ) + tan2(θ) (1/cosθ = secθ)
= (sec(θ) - tan(θ))2
c. (sin(θ) + cos(θ))/sin(θ) - (cos(θ) - sin(θ))/cos(θ)
Get a common denominator sin(θ)cos(θ):
= ( (sin(θ) + cos(θ))/sin(θ) )*(cos(θ)/cos(θ)) - ( (cos(θ) - sin(θ))/cos(θ) )*(sin(θ)/sin(θ))
= ( sin(θ)cos(θ) + cos2(θ) )/(sin(θ)cos(θ)) - ( cos(θ)sin(θ) - sin2(θ) )/(sin(θ)cos(θ)) (multiply through)
= ( sin(θ)cos(θ) + cos2(θ) - cos(θ)sin(θ) + sin2(θ) ) / (sin(θ)cos(θ)) (add the fractions)
= ( cos2(θ) + sin2(θ) )/(sin(θ)cos(θ)) (cancel terms)
= 1/(sin(θ)cos(θ)) (Pythagorean Identity)
= csc(θ)sec(θ) (def of cscθ and secθ)