Arthur D. answered 11/29/17
Tutor
5.0
(270)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
A.) is there a typo here ? should secx be 1 ??
B.) cscx-sinx=cosxcotx
(1/sinx)-(sinx)=
(1/sinx)-(sin2x/sinx)=
(1-sin2x)/(sinx)=
(cos2x)/(sinx)=
(cosx)(cosx)/(sinx)=
(cosx)(cosx/sinx)=
(cosx)(cotx)