
Arturo O. answered 11/25/17
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I assume you have a tank filled with liquid to the top (station 1), and that it is leaking through a small hole on the side (station 2), and you want to find the speed of the flow v2 at the leak.
You must reference the top of the tank and the height of the hole to the same reference point. You can use the height h above the ground, as long as both heights are referenced to ground level. Then Bernoulli's equation gives
p1 + ρgh1 + ρv12/2 = p2 + ρgh2 + ρv22/2
p1 ≅ p2 ⇒
ρgh1 + ρv12/2 = ρgh2 + ρv22/2
gh1 + v12/2 = gh2 + v22/2
If the horizontal surface area of the the tank is much larger than the area of the hole, then v1 is negligible compared to v2, and the continuity equation allows you to use the approximation
gh1 = gh2 + v22/2 ⇒
v2 = √[2g(h1 - h2)]
The is Torricelli's formula. But note that h1 - h2 is the difference in height between the top of the liquid and the hole. So if the tank is filled to the top, and the hole is in the middle, then h1 - h2 is half of the vertical length of the tank, which in this problem is half of 5 meters = 2.5 meters. That is the same as
h1 - h2 = (10 + 5)m - (10 + 5/2)m = 2.5 m
Does this answer your question?