a) Rider Speed = ω·r
- ω = angular frequency = 2pi/period = 2pi/32 = pi/16 ≅ 0.2 m/s
- r = radius = 5 m
b) Vertically, the drop is:
h(t) = -4.9t2
There is no v0 in the vertical direction (the toy is dropped, not thrown). The height dropped is -5 - 1.75 = -6.75 m:
-6.75 = -4.9t2
Solve for t. The horizontal displacement of the toy from the base of the ride is v0t where v0 is the speed of the rider at the top of the ride (from part (a)) and t is the time you just computed.
Kollin F.
He reduced it from 1/2gt^2 and just skipped the step bringing in half of the gravity instead. At least that's what I'm assuming. But my question is if you are looking at the height from the top of the Ferris wheel why isn't it 10+1.75?
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09/23/19
Stephanie M.
Where does the -4.9 come from? I was trying to figure out a similar problem and since that number isn't in the problem, I don't understand what it is.09/21/19