line L passes through (14,-5) and line P is the graoh of 7x-5y=11. If L is perpendicular to line P what is the slope intercept form equation of L?

Question

complete the equation of the line in slope intercept form.  If any # in the equation is not an integer, enter it as a fraction in simplest form

Answer 1

The slope intersection form will be

y = (7x/5) - 11/5

The slope of this line is 7/5 and the one of the perpendicular is -5/7

and the equation will be y=(-5x/7) + b; to find b we use the point given and obtain:

-5 =(-5*14/7) +b

b= -5 + 10

b= 5

The new equation is

y = (-5x/7) + 5 = 7Y + 5X = 35

 

Answer 2

I have a question

shouldn,t the 11 be divided by 5 also and be negative  ?

or

y=7/5x-11/5   

also the line perpendicular has a slope of -1 times the original slope

 

 

Answer 3

We're going to have to start with putting P in slope-intercept form.  We end up with y=5/7x+11.  A line perpendicular will have the negative reciprocal slope of -7/5.  

 

Plug in what we have now for y=mx+b and we get -5=(-7/5)14+b.

 

So, b=73/5 .

 

Our equation then is y=-7/5x+73/5.