
Arturo O. answered 11/18/17
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
If the function z(x,y) is "well-behaved" then
∂2z/∂r∂ϴ = ∂/∂θ (∂z/∂r) = ∂/∂r (∂z/∂θ),
i.e., the order of differentiation is interchangeable. Just differentiate z with respect to r, and then differentiate the result with respect to θ, or do this in opposite order. But first you must express z as a function of r and θ. You will need to replace the x in z with rcosθ and the y in z with rsinθ. If you give us the actual function z(x,y) we could help you more.