passing through -2,-11 and perpendicular to x+4y=8

Question

need help

Answer 1

4y = 8 - x

 

y = (8-x)/4 = 2 - (1/4)x = (-1/4)X + 2

 

The slope of the given line is (-1/4)

 

Perpendicular lines have slopes that are negative reciprocals.

 

The slope of the perpendicular line is 4

 

(-2,-11) means x=-2 when y = -11 and it has slope M=4

 

y  = m x + b ---> b = y - mx

 

b = -11 -  4*-2  

    = -11 - (-8)

    = -3

 

y = 4x + -3