the decibel scale is logarithmic, not linear, meaning that
10 dB increase corresponds to a 10-fold increase in sound intensity
20 dB increase corresponds to a 100-fold increase in intensity
what that means for this scenario is that the sound level of 100 cars is 20 dB higher than the sound level of one car, so the end value here is
100 dB (total) - 20 dB (increase) = 80 dB (sound level of one car)
so the sound intensity level produced by one car is 80 dB