I need a step by step explanation on how to answer the question stated below as soon as possible, thank you!!!

Question

Find the z score such that 83% of the distraction is contained within z standard devotions of the mean. 

Answer 1

You want to use either a Z table or technology like Microsoft Excel in order to convert the probability value of 0.8300 over into a Z value. When I do it using a precise calculator I find that the exact Z score here is approximately 1.372.

Meaning that the Z score such that 83% of the distribution is contained within Z standard deviations of the mean is +/- 1.372