The function f is not one to one since the two sets {a,b} and {b,c} are not equal but f({a,b})=f({b,c})=2. The function is not onto the set of natural numbers since for example there is no subset of the set {a,b,c} of more than 3 elements. But of course the function is onto its image, which is the set {0,1,2,3}. Every function is onto its image by the definition of the image set.
Ahmet Yasin A.
asked 11/15/17Is f one-to-one? Is f onto? Prove or give a counterexample.
Define f(x) : P({a,b,c}) →N as follows:
for all A ∈P({a,b,c}), f(A) = the number of elements in A.
( P is a power set.)
Is f one-to-one? Prove or give a counterexample.
Is f onto? Prove or give a counterexample.
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Ggg G.
(d) Given a function F : P({a, b, c}) → Z is defined by F(A) = |A| for all A ∈ P({a, b, c}). i. Is F a one-to-one function? Prove or give a counter-example. ii. Is F an onto function? Prove or give a counter-example.12/16/22